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Pressure ratio through a duct.

submitted by usedoilanalysis to Fluiddynamics 2.7 yearsAug 31, 2022 13:05:13 ago (+0/-0)     (Fluiddynamics)

The velocity of air through a duct is entirely dependent on the pressure ratio at the throat, and the inlet. Therefore at low vehicle speeds a duct can have 1 bar head, and 1 bar at the outlet. As the vehicle speed increases, the head pressure also increases, meanwhile, the duct pressure decreases at any and all throats, which in turn reduces the pressure at the outlet. The increased head pressure, and reduced outlet pressure together increase the pressure ratio at each throat.

https://imgr1.auto-motor-und-sport.de/Carlos-Sainz-Ferrari-Formel-1-GP-Monaco-28-Mai-2022-169Gallery-e1398dda-1903619.jpg

These strakes increase head pressure, as they divert air outward, the inner most strake and the body become the path of least resistance. Now these strakes also restrict air from moving into the back of the floor. Which in effect is lowering the back pressure of the throat created between the inner-most strake and the body. When the pressure ratio reaches ~2:1, you have choked flow. Once you have choked flow, the passage to the back of the floor becomes restricted, which increases the suction behind the strake which pulls the floor downward at that point. However choked flow is very lossy, unless it is carefully controlled. The shape of the outlet has to be carefully designed to exploit the fact that you can accelerate choked flow with careful expansion of the duct.

Not only that, but all subsequent ducts must have this careful sizing in mind, otherwise there are great losses, and flow instability.

https://youtu.be/45w1-lwFSzM?t=1053

You can see in this experiment how critical duct geometry is to maintain low pressure, low loss flow.


4 comments block


[ - ] Thatguy 1 point 2.7 yearsAug 31, 2022 13:23:53 ago (+1/-0)

When the pressure gets to me I become exhausted. My temperature drops and I become cool. Rapid expansion has that effect on me.

[ - ] Crackinjokes 0 points 2.7 yearsAug 31, 2022 14:28:45 ago (+0/-0)

I had no idea formula 1 cars were open at the bottom like that.

Why is the pressure ratio of 2 to 1 significant for choked flow? And is that only true at one at mcpheric pressure and a certain air density?

[ - ] usedoilanalysis [op] 0 points 2.7 yearsAug 31, 2022 15:01:08 ago (+0/-0)

The pressure ratio is relevant to air, because it's a dimensionless number. Humidity, temperature, and elevation will change gas density, but the ratio remains constant, as long as the substance is constant. Most gases have a choking range between .487 and .52, that is when the downstream pressure is .48 to .52 percent of the upstream pressure.

This phenomena is what allowed the J-58 engine to work at 80,000 feet. In order to produce the thrust required to go Mach 3.4, the pressure ratio of the engine needs to be 64:1 or 940bar of inlet pressure at sea level. It's very hard to do that when you're at sea level and the outlet pressure is 14 psi. However, at 80,000 feet, the outlet pressure is .4psi, then to get that 64:1 ratio you only need 25bar at the inlet because the ratio remains constant. The ram jet provided 14 bar and the jet engine provided the rest.

[ - ] lord_nougat 0 points 2.7 yearsAug 31, 2022 13:27:42 ago (+0/-0)

Needs moar TURBO ENCABULATION!